7/(2x5^3)+3(4x5^2)

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Solution for 7/(2x5^3)+3(4x5^2) equation: 


D( x )

2*x^(5^3) = 0

2*x^(5^3) = 0

2*x^(5^3) = 0

2*x^125 = 0 // : 2

x^125 = 0

x = 0

x in (-oo:0) U (0:+oo)

3*4*x^(5^2)+7/(2*x^(5^3)) = 0

12*x^25+7/2*x^-125 = 0

t_1 = x^25

12*t_1^1+7/2*t_1^-5 = 0

12*t_1+7/2*t_1^-5 = 0

t_1*(7/2*t_1^-6+12) = 0

7/2*t_1^-6 = -12 // : 7/2

t_1^-6 = -24/7

-6 < 0

1/(t_1^6) = -24/7 // * t_1^6

1 = -24/7*t_1^6 // : -24/7

-7/24 = t_1^6

t_1 = 0

t_1 = 0

t_1 = 0

x^25+0 = 0

x^25 = 0

1*x^25 = 0 // : 1

x^25 = 0

x = 0

x in { 0} 

x belongs to the empty set

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